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512214032010437 is a prime number
BaseRepresentation
bin111010001110110110001111…
…1011011010100110011000101
32111011121011221120122102100122
41310131230133123110303011
51014114103314143313222
65013215513340351325
7212614146132153551
oct16435543733246305
92434534846572318
10512214032010437
1113923082974aa09
1249546616b45545
1318ca676450b6a3
14906b411966861
153e33ce0aeaa42
hex1d1db1f6d4cc5

512214032010437 has 2 divisors, whose sum is σ = 512214032010438. Its totient is φ = 512214032010436.

The previous prime is 512214032010353. The next prime is 512214032010487. The reversal of 512214032010437 is 734010230412215.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 492168944984161 + 20045087026276 = 22184881^2 + 4477174^2 .

It is a cyclic number.

It is not a de Polignac number, because 512214032010437 - 210 = 512214032009413 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 512214032010397 and 512214032010406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (512214032010487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256107016005218 + 256107016005219.

It is an arithmetic number, because the mean of its divisors is an integer number (256107016005219).

Almost surely, 2512214032010437 is an apocalyptic number.

It is an amenable number.

512214032010437 is a deficient number, since it is larger than the sum of its proper divisors (1).

512214032010437 is an equidigital number, since it uses as much as digits as its factorization.

512214032010437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 35.

The spelling of 512214032010437 in words is "five hundred twelve trillion, two hundred fourteen billion, thirty-two million, ten thousand, four hundred thirty-seven".