Base | Representation |
---|---|
bin | 101111101101001100… |
… | …110111100000101111 |
3 | 11220012220101122220111 |
4 | 233231030313200233 |
5 | 1314401344313201 |
6 | 35310532400451 |
7 | 3462245426320 |
oct | 575514674057 |
9 | 156186348814 |
10 | 51224213551 |
11 | 1a7a6807895 |
12 | 9b16a76127 |
13 | 4aa4591444 |
14 | 269d164447 |
15 | 14ec0b4b51 |
hex | bed33782f |
51224213551 has 4 divisors (see below), whose sum is σ = 58541958352. Its totient is φ = 43906468752.
The previous prime is 51224213471. The next prime is 51224213603. The reversal of 51224213551 is 15531242215.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15531242215 = 5 ⋅3106248443.
It is a cyclic number.
It is not a de Polignac number, because 51224213551 - 233 = 42634278959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51224216551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3658872390 + ... + 3658872403.
It is an arithmetic number, because the mean of its divisors is an integer number (14635489588).
Almost surely, 251224213551 is an apocalyptic number.
51224213551 is a deficient number, since it is larger than the sum of its proper divisors (7317744801).
51224213551 is an equidigital number, since it uses as much as digits as its factorization.
51224213551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7317744800.
The product of its digits is 12000, while the sum is 31.
Adding to 51224213551 its reverse (15531242215), we get a palindrome (66755455766).
The spelling of 51224213551 in words is "fifty-one billion, two hundred twenty-four million, two hundred thirteen thousand, five hundred fifty-one".
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