Base | Representation |
---|---|
bin | 10111010011001011001001… |
… | …00100010111101111010100 |
3 | 20201102010222110210220201122 |
4 | 23221211210210113233110 |
5 | 23203424022121130004 |
6 | 300545353310143112 |
7 | 13535463366216356 |
oct | 1351454444275724 |
9 | 221363873726648 |
10 | 51236352130004 |
11 | 15364240059528 |
12 | 58b5b467b1a98 |
13 | 227874b3bc382 |
14 | c91bd1a4d0d6 |
15 | 5dcb95e66cbe |
hex | 2e9964917bd4 |
51236352130004 has 6 divisors (see below), whose sum is σ = 89663616227514. Its totient is φ = 25618176065000.
The previous prime is 51236352129997. The next prime is 51236352130037. The reversal of 51236352130004 is 40003125363215.
It is a happy number.
It can be written as a sum of positive squares in only one way, i.e., 41942073112900 + 9294279017104 = 6476270^2 + 3048652^2 .
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6404544016247 + ... + 6404544016254.
It is an arithmetic number, because the mean of its divisors is an integer number (14943936037919).
Almost surely, 251236352130004 is an apocalyptic number.
It is an amenable number.
51236352130004 is a deficient number, since it is larger than the sum of its proper divisors (38427264097510).
51236352130004 is a wasteful number, since it uses less digits than its factorization.
51236352130004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12809088032505 (or 12809088032503 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 51236352130004 its reverse (40003125363215), we get a palindrome (91239477493219).
The spelling of 51236352130004 in words is "fifty-one trillion, two hundred thirty-six billion, three hundred fifty-two million, one hundred thirty thousand, four".
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