5124010013 has 2 divisors, whose sum is σ = 5124010014. Its totient is φ = 5124010012.

The previous prime is 5124009997. The next prime is 5124010019. The reversal of 5124010013 is 3100104215.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3349747129 + 1774262884 = 57877^2 + 42122^2 .

It is a cyclic number.

It is not a de Polignac number, because 5124010013 - 2⁴ = 5124009997 is a prime.

It is a super-2 number, since 2×5124010013² = 52510957226648520338, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5124009973 and 5124010000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5124010019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562005006 + 2562005007.

It is an arithmetic number, because the mean of its divisors is an integer number (2562005007).

Almost surely, 2^5124010013 is an apocalyptic number.

It is an amenable number.

5124010013 is a deficient number, since it is larger than the sum of its proper divisors (1).

5124010013 is an equidigital number, since it uses as much as digits as its factorization.

5124010013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 5124010013 is about 71582.1906133083. The cubic root of 5124010013 is about 1723.9975987257.

Adding to 5124010013 its reverse (3100104215), we get a palindrome (8224114228).

The spelling of 5124010013 in words is "five billion, one hundred twenty-four million, ten thousand, thirteen".