Base | Representation |
---|---|
bin | 111010010001010011101011… |
… | …1111100000100011111110111 |
3 | 2111012210111122120011110210202 |
4 | 1310202213113330010133313 |
5 | 1014140123233033120010 |
6 | 5014035111130111115 |
7 | 212650445501453615 |
oct | 16442472774043767 |
9 | 2435714576143722 |
10 | 512552135051255 |
11 | 13935115a036792 |
12 | 495a0054b7b49b |
13 | 18ccc5c73b20a0 |
14 | 907d9273606b5 |
15 | 3e3c9cd4846a5 |
hex | 1d229d7f047f7 |
512552135051255 has 16 divisors (see below), whose sum is σ = 662376542627520. Its totient is φ = 378499194882048.
The previous prime is 512552135051219. The next prime is 512552135051303. The reversal of 512552135051255 is 552150531255215.
It is a cyclic number.
It is not a de Polignac number, because 512552135051255 - 220 = 512552134002679 is a prime.
It is a super-2 number, since 2×5125521350512552 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21405719 + ... + 38513751.
It is an arithmetic number, because the mean of its divisors is an integer number (41398533914220).
Almost surely, 2512552135051255 is an apocalyptic number.
512552135051255 is a deficient number, since it is larger than the sum of its proper divisors (149824407576265).
512552135051255 is a wasteful number, since it uses less digits than its factorization.
512552135051255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17568970.
The product of its (nonzero) digits is 1875000, while the sum is 47.
The spelling of 512552135051255 in words is "five hundred twelve trillion, five hundred fifty-two billion, one hundred thirty-five million, fifty-one thousand, two hundred fifty-five".
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