Base | Representation |
---|---|
bin | 101111110000000011… |
… | …001010101100101001 |
3 | 11220100020022120210211 |
4 | 233300003022230221 |
5 | 1320001113033340 |
6 | 35315400541121 |
7 | 3463365554254 |
oct | 576003125451 |
9 | 156306276724 |
10 | 51272002345 |
11 | 1a820788263 |
12 | 9b2aa817a1 |
13 | 4ab1454235 |
14 | 26a564409b |
15 | 15013a45ea |
hex | bf00cab29 |
51272002345 has 4 divisors (see below), whose sum is σ = 61526402820. Its totient is φ = 41017601872.
The previous prime is 51272002333. The next prime is 51272002399. The reversal of 51272002345 is 54320027215.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 29504245824 + 21767756521 = 171768^2 + 147539^2 .
It is a cyclic number.
It is not a de Polignac number, because 51272002345 - 27 = 51272002217 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5127200230 + ... + 5127200239.
It is an arithmetic number, because the mean of its divisors is an integer number (15381600705).
Almost surely, 251272002345 is an apocalyptic number.
It is an amenable number.
51272002345 is a deficient number, since it is larger than the sum of its proper divisors (10254400475).
51272002345 is a wasteful number, since it uses less digits than its factorization.
51272002345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10254400474.
The product of its (nonzero) digits is 16800, while the sum is 31.
The spelling of 51272002345 in words is "fifty-one billion, two hundred seventy-two million, two thousand, three hundred forty-five".
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