Base | Representation |
---|---|
bin | 101111110001101110… |
… | …011110110101010111 |
3 | 11220102012020211111112 |
4 | 233301232132311113 |
5 | 1320030313243411 |
6 | 35322243525235 |
7 | 3464156642363 |
oct | 576156366527 |
9 | 156365224445 |
10 | 51300134231 |
11 | 1a835652155 |
12 | 9b3838981b |
13 | 4ab7223b18 |
14 | 26a92882a3 |
15 | 1503aaeb8b |
hex | bf1b9ed57 |
51300134231 has 2 divisors, whose sum is σ = 51300134232. Its totient is φ = 51300134230.
The previous prime is 51300134219. The next prime is 51300134239. The reversal of 51300134231 is 13243100315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51300134231 - 226 = 51233025367 is a prime.
It is a super-2 number, since 2×513001342312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51300134197 and 51300134206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51300134239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25650067115 + 25650067116.
It is an arithmetic number, because the mean of its divisors is an integer number (25650067116).
Almost surely, 251300134231 is an apocalyptic number.
51300134231 is a deficient number, since it is larger than the sum of its proper divisors (1).
51300134231 is an equidigital number, since it uses as much as digits as its factorization.
51300134231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 51300134231 its reverse (13243100315), we get a palindrome (64543234546).
The spelling of 51300134231 in words is "fifty-one billion, three hundred million, one hundred thirty-four thousand, two hundred thirty-one".
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