Base | Representation |
---|---|
bin | 100101010100110110010… |
… | …1011101100011110011011 |
3 | 200011102110112001011211120 |
4 | 1022221230223230132123 |
5 | 1133022232133020430 |
6 | 14524410203100323 |
7 | 1036426352314032 |
oct | 112515453543633 |
9 | 20142415034746 |
10 | 5130014345115 |
11 | 16a86993a4360 |
12 | 6aa2935116a3 |
13 | 2b29b1c1c31a |
14 | 13a418b07719 |
15 | 8d69b96a610 |
hex | 4aa6caec79b |
5130014345115 has 16 divisors (see below), whose sum is σ = 8954206857216. Its totient is φ = 2487279682400.
The previous prime is 5130014345101. The next prime is 5130014345147. The reversal of 5130014345115 is 5115434100315.
It is a happy number.
It is not a de Polignac number, because 5130014345115 - 25 = 5130014345083 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15545497851 + ... + 15545498180.
It is an arithmetic number, because the mean of its divisors is an integer number (559637928576).
Almost surely, 25130014345115 is an apocalyptic number.
5130014345115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5130014345115 is a deficient number, since it is larger than the sum of its proper divisors (3824192512101).
5130014345115 is a wasteful number, since it uses less digits than its factorization.
5130014345115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31090996050.
The product of its (nonzero) digits is 18000, while the sum is 33.
The spelling of 5130014345115 in words is "five trillion, one hundred thirty billion, fourteen million, three hundred forty-five thousand, one hundred fifteen".
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