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51300412800 = 2735272138389
BaseRepresentation
bin101111110001101111…
…100010110110000000
311220102012202222121220
4233301233202312000
51320030401202200
635322253515040
73464162212500
oct576157426600
9156365688556
1051300412800
111a83582247a
129b384a2a80
134ab72c0860
1426a931ba00
151503b174a0
hexbf1be2d80

51300412800 has 576 divisors, whose sum is σ = 211702856400. Its totient is φ = 10822533120.

The previous prime is 51300412771. The next prime is 51300412811. The reversal of 51300412800 is 821400315.

It is a super-3 number, since 3×513004128003 (a number of 33 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 6111006 + ... + 6119394.

Almost surely, 251300412800 is an apocalyptic number.

51300412800 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 51300412800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (105851428200).

51300412800 is an abundant number, since it is smaller than the sum of its proper divisors (160402443600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

51300412800 is a wasteful number, since it uses less digits than its factorization.

51300412800 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8443 (or 8419 counting only the distinct ones).

The product of its (nonzero) digits is 960, while the sum is 24.

The spelling of 51300412800 in words is "fifty-one billion, three hundred million, four hundred twelve thousand, eight hundred".