513004300523423 has 4 divisors (see below), whose sum is σ = 513521963794368. Its totient is φ = 512486637252480.

The previous prime is 513004300523419. The next prime is 513004300523453. The reversal of 513004300523423 is 324325003400315.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 513004300523423 - 2² = 513004300523419 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (513004300523453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 258831633986 + ... + 258831635967.

It is an arithmetic number, because the mean of its divisors is an integer number (128380490948592).

Almost surely, 2^{513004300523423} is an apocalyptic number.

513004300523423 is a deficient number, since it is larger than the sum of its proper divisors (517663270945).

513004300523423 is an equidigital number, since it uses as much as digits as its factorization.

513004300523423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 517663270944.

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 513004300523423 its reverse (324325003400315), we get a palindrome (837329303923738).

The spelling of 513004300523423 in words is "five hundred thirteen trillion, four billion, three hundred million, five hundred twenty-three thousand, four hundred twenty-three".