Base | Representation |
---|---|
bin | 101111110001110001… |
… | …110110001001000110 |
3 | 11220102020220122020121 |
4 | 233301301312021012 |
5 | 1320031030004014 |
6 | 35322314452154 |
7 | 3464200304464 |
oct | 576161661106 |
9 | 156366818217 |
10 | 51301016134 |
11 | 1a8360a47a5 |
12 | 9b3873405a |
13 | 4ab7472364 |
14 | 26a9437834 |
15 | 1503bd6124 |
hex | bf1c76246 |
51301016134 has 4 divisors (see below), whose sum is σ = 76951524204. Its totient is φ = 25650508066.
The previous prime is 51301016111. The next prime is 51301016147. The reversal of 51301016134 is 43161010315.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43161010315 = 5 ⋅8632202063.
It is a junction number, because it is equal to n+sod(n) for n = 51301016099 and 51301016108.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12825254032 + ... + 12825254035.
It is an arithmetic number, because the mean of its divisors is an integer number (19237881051).
Almost surely, 251301016134 is an apocalyptic number.
51301016134 is a deficient number, since it is larger than the sum of its proper divisors (25650508070).
51301016134 is a wasteful number, since it uses less digits than its factorization.
51301016134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25650508069.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 51301016134 its reverse (43161010315), we get a palindrome (94462026449).
The spelling of 51301016134 in words is "fifty-one billion, three hundred one million, sixteen thousand, one hundred thirty-four".
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