513051749503 has 4 divisors (see below), whose sum is σ = 513057799240. Its totient is φ = 513045699768.

The previous prime is 513051749501. The next prime is 513051749513. The reversal of 513051749503 is 305947150315.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 513051749503 - 2¹ = 513051749501 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 513051749503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (513051749501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2895825 + ... + 3067882.

It is an arithmetic number, because the mean of its divisors is an integer number (128264449810).

Almost surely, 2^513051749503 is an apocalyptic number.

513051749503 is a deficient number, since it is larger than the sum of its proper divisors (6049737).

513051749503 is an equidigital number, since it uses as much as digits as its factorization.

513051749503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6049736.

The product of its (nonzero) digits is 283500, while the sum is 43.

Adding to 513051749503 its reverse (305947150315), we get a palindrome (818998899818).

The spelling of 513051749503 in words is "five hundred thirteen billion, fifty-one million, seven hundred forty-nine thousand, five hundred three".