Base | Representation |
---|---|
bin | 1110111011101000101… |
… | …00011001001110000101 |
3 | 1211001021112000002001122 |
4 | 13131310110121032011 |
5 | 31401212432031321 |
6 | 1031405414003325 |
7 | 52031631146225 |
oct | 7356424311605 |
9 | 1731245002048 |
10 | 513052611461 |
11 | 1886479076a5 |
12 | 83524346545 |
13 | 394c43b0700 |
14 | 1ab90966085 |
15 | d52b9c88ab |
hex | 7774519385 |
513052611461 has 24 divisors (see below), whose sum is σ = 560750532480. Its totient is φ = 469161428736.
The previous prime is 513052611451. The next prime is 513052611497. The reversal of 513052611461 is 164116250315.
It is a de Polignac number, because none of the positive numbers 2k-513052611461 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (513052611451) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 46724870 + ... + 46735848.
It is an arithmetic number, because the mean of its divisors is an integer number (23364605520).
Almost surely, 2513052611461 is an apocalyptic number.
513052611461 is the 413543-rd octagonal number.
It is an amenable number.
513052611461 is a deficient number, since it is larger than the sum of its proper divisors (47697921019).
513052611461 is a wasteful number, since it uses less digits than its factorization.
With its predecessor (513052611460) it forms a Ruth-Aaron pair, since the sum of their prime factors is the same (13565).
513052611461 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13565 (or 13552 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 35.
Adding to 513052611461 its reverse (164116250315), we get a palindrome (677168861776).
The spelling of 513052611461 in words is "five hundred thirteen billion, fifty-two million, six hundred eleven thousand, four hundred sixty-one".
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