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513124159421 is a prime number
BaseRepresentation
bin1110111011110001001…
…01010100111110111101
31211001110111122002102002
413131320211110332331
531401334241100141
61031420451312045
752033460250656
oct7357045247675
91731414562362
10513124159421
11188684235745
12835442ab625
1339506171993
141ab9a26c52d
15d532e0ce9b
hex7778954fbd

513124159421 has 2 divisors, whose sum is σ = 513124159422. Its totient is φ = 513124159420.

The previous prime is 513124159417. The next prime is 513124159423. The reversal of 513124159421 is 124951421315.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 483044460196 + 30079699225 = 695014^2 + 173435^2 .

It is a cyclic number.

It is not a de Polignac number, because 513124159421 - 22 = 513124159417 is a prime.

Together with 513124159423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (513124159423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256562079710 + 256562079711.

It is an arithmetic number, because the mean of its divisors is an integer number (256562079711).

Almost surely, 2513124159421 is an apocalyptic number.

It is an amenable number.

513124159421 is a deficient number, since it is larger than the sum of its proper divisors (1).

513124159421 is an equidigital number, since it uses as much as digits as its factorization.

513124159421 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 43200, while the sum is 38.

The spelling of 513124159421 in words is "five hundred thirteen billion, one hundred twenty-four million, one hundred fifty-nine thousand, four hundred twenty-one".