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51333351141 = 359290018933
BaseRepresentation
bin101111110011101101…
…001100011011100101
311220111111202102112110
4233303231030123211
51320112314214031
635325431511233
73465042166602
oct576355143345
9156444672473
1051333351141
111a85237a546
129b47528519
134ac10840b7
1426ad8536a9
151506971c46
hexbf3b4c6e5

51333351141 has 8 divisors (see below), whose sum is σ = 69604544160. Its totient is φ = 33642196112.

The previous prime is 51333351133. The next prime is 51333351151. The reversal of 51333351141 is 14115333315.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51333351141 - 23 = 51333351133 is a prime.

It is a super-2 number, since 2×513333511412 (a number of 22 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 51333351099 and 51333351108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51333351151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 145009290 + ... + 145009643.

It is an arithmetic number, because the mean of its divisors is an integer number (8700568020).

Almost surely, 251333351141 is an apocalyptic number.

It is an amenable number.

51333351141 is a deficient number, since it is larger than the sum of its proper divisors (18271193019).

51333351141 is a wasteful number, since it uses less digits than its factorization.

51333351141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 290018995.

The product of its digits is 8100, while the sum is 30.

Adding to 51333351141 its reverse (14115333315), we get a palindrome (65448684456).

The spelling of 51333351141 in words is "fifty-one billion, three hundred thirty-three million, three hundred fifty-one thousand, one hundred forty-one".

Divisors: 1 3 59 177 290018933 870056799 17111117047 51333351141