513400420151 has 2 divisors, whose sum is σ = 513400420152. Its totient is φ = 513400420150.

The previous prime is 513400420139. The next prime is 513400420153. The reversal of 513400420151 is 151024004315.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-513400420151 is a prime.

It is a super-2 number, since 2×513400420151² (a number of 24 digits) contains 22 as substring.

Together with 513400420153, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 513400420151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (513400420153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256700210075 + 256700210076.

It is an arithmetic number, because the mean of its divisors is an integer number (256700210076).

Almost surely, 2^513400420151 is an apocalyptic number.

513400420151 is a deficient number, since it is larger than the sum of its proper divisors (1).

513400420151 is an equidigital number, since it uses as much as digits as its factorization.

513400420151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 513400420151 its reverse (151024004315), we get a palindrome (664424424466).

The spelling of 513400420151 in words is "five hundred thirteen billion, four hundred million, four hundred twenty thousand, one hundred fifty-one".