Base | Representation |
---|---|
bin | 101111110100001110… |
… | …101011101101011101 |
3 | 11220112010021102212212 |
4 | 233310032223231131 |
5 | 1320122041130023 |
6 | 35330344010205 |
7 | 3465206622146 |
oct | 576416535535 |
9 | 156463242785 |
10 | 51342130013 |
11 | 1a857326209 |
12 | 9b4a460965 |
13 | 4ac2b38bb5 |
14 | 26b0a9aacd |
15 | 1507607e78 |
hex | bf43abb5d |
51342130013 has 2 divisors, whose sum is σ = 51342130014. Its totient is φ = 51342130012.
The previous prime is 51342130003. The next prime is 51342130019. The reversal of 51342130013 is 31003124315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 48584094724 + 2758035289 = 220418^2 + 52517^2 .
It is a cyclic number.
It is not a de Polignac number, because 51342130013 - 212 = 51342125917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51342130019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25671065006 + 25671065007.
It is an arithmetic number, because the mean of its divisors is an integer number (25671065007).
Almost surely, 251342130013 is an apocalyptic number.
It is an amenable number.
51342130013 is a deficient number, since it is larger than the sum of its proper divisors (1).
51342130013 is an equidigital number, since it uses as much as digits as its factorization.
51342130013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 51342130013 its reverse (31003124315), we get a palindrome (82345254328).
The spelling of 51342130013 in words is "fifty-one billion, three hundred forty-two million, one hundred thirty thousand, thirteen".
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