Search a number
-
+
51343253587807 is a prime number
BaseRepresentation
bin10111010110010010010000…
…11001000100011101011111
320201210100220121202122021121
423223021020121010131133
523212201440404302212
6301110433131311411
713546266454503166
oct1353111031043537
9221710817678247
1051343253587807
11153a5608152a65
1259127bb8ab567
13228585698194c
14c970534d83dd
155e0851002d07
hex2eb24864475f

51343253587807 has 2 divisors, whose sum is σ = 51343253587808. Its totient is φ = 51343253587806.

The previous prime is 51343253587771. The next prime is 51343253587811. The reversal of 51343253587807 is 70878535234315.

51343253587807 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 51343253587807 - 27 = 51343253587679 is a prime.

It is a super-2 number, since 2×513432535878072 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51343253582807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25671626793903 + 25671626793904.

It is an arithmetic number, because the mean of its divisors is an integer number (25671626793904).

Almost surely, 251343253587807 is an apocalyptic number.

51343253587807 is a deficient number, since it is larger than the sum of its proper divisors (1).

51343253587807 is an equidigital number, since it uses as much as digits as its factorization.

51343253587807 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84672000, while the sum is 61.

The spelling of 51343253587807 in words is "fifty-one trillion, three hundred forty-three billion, two hundred fifty-three million, five hundred eighty-seven thousand, eight hundred seven".