Base | Representation |
---|---|
bin | 1110111100110001001… |
… | …01010100111011100101 |
3 | 1211002211220211221112221 |
4 | 13132120211110323211 |
5 | 31403434210430432 |
6 | 1031550030312341 |
7 | 52052666500444 |
oct | 7363045247345 |
9 | 1732756757487 |
10 | 513661030117 |
11 | 18892a295634 |
12 | 836740586b1 |
13 | 39590466151 |
14 | 1ac0b6a0d5b |
15 | d56510ab97 |
hex | 7798954ee5 |
513661030117 has 2 divisors, whose sum is σ = 513661030118. Its totient is φ = 513661030116.
The previous prime is 513661030081. The next prime is 513661030153. The reversal of 513661030117 is 711030166315.
It is a balanced prime because it is at equal distance from previous prime (513661030081) and next prime (513661030153).
It can be written as a sum of positive squares in only one way, i.e., 417730835041 + 95930195076 = 646321^2 + 309726^2 .
It is a cyclic number.
It is not a de Polignac number, because 513661030117 - 27 = 513661029989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513661030177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256830515058 + 256830515059.
It is an arithmetic number, because the mean of its divisors is an integer number (256830515059).
Almost surely, 2513661030117 is an apocalyptic number.
It is an amenable number.
513661030117 is a deficient number, since it is larger than the sum of its proper divisors (1).
513661030117 is an equidigital number, since it uses as much as digits as its factorization.
513661030117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340, while the sum is 34.
The spelling of 513661030117 in words is "five hundred thirteen billion, six hundred sixty-one million, thirty thousand, one hundred seventeen".
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