Base | Representation |
---|---|
bin | 1110111101011101010… |
… | …01100000010100101111 |
3 | 1211010210201102202020121 |
4 | 13132232221200110233 |
5 | 31410213443132421 |
6 | 1032050453025411 |
7 | 52065113212306 |
oct | 7365651402457 |
9 | 1733721382217 |
10 | 514031224111 |
11 | 188aaa252889 |
12 | 83758025267 |
13 | 3961c06cb52 |
14 | 1ac4490743d |
15 | d587882d41 |
hex | 77aea6052f |
514031224111 has 16 divisors (see below), whose sum is σ = 546034763520. Its totient is φ = 482849424640.
The previous prime is 514031224087. The next prime is 514031224139. The reversal of 514031224111 is 111422130415.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 514031224111 - 25 = 514031224079 is a prime.
It is a super-2 number, since 2×5140312241112 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (514031224181) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1122591 + ... + 1512703.
It is an arithmetic number, because the mean of its divisors is an integer number (34127172720).
Almost surely, 2514031224111 is an apocalyptic number.
514031224111 is a deficient number, since it is larger than the sum of its proper divisors (32003539409).
514031224111 is a wasteful number, since it uses less digits than its factorization.
514031224111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 391166.
The product of its (nonzero) digits is 960, while the sum is 25.
Adding to 514031224111 its reverse (111422130415), we get a palindrome (625453354526).
The spelling of 514031224111 in words is "five hundred fourteen billion, thirty-one million, two hundred twenty-four thousand, one hundred eleven".
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