Base | Representation |
---|---|
bin | 101111110111111011… |
… | …111101100011000001 |
3 | 11220200110022120212120 |
4 | 233313323331203001 |
5 | 1320234002044301 |
6 | 35340445114453 |
7 | 3466563414546 |
oct | 576773754301 |
9 | 156613276776 |
10 | 51404331201 |
11 | 1a88944a953 |
12 | 9b67258a29 |
13 | 4b029a6a32 |
14 | 26b904cbcd |
15 | 150cce2e36 |
hex | bf7efd8c1 |
51404331201 has 8 divisors (see below), whose sum is σ = 68736628704. Its totient is φ = 34170793920.
The previous prime is 51404331197. The next prime is 51404331211. The reversal of 51404331201 is 10213340415.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 51404331201 - 22 = 51404331197 is a prime.
It is not an unprimeable number, because it can be changed into a prime (51404331211) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24688840 + ... + 24690921.
It is an arithmetic number, because the mean of its divisors is an integer number (8592078588).
Almost surely, 251404331201 is an apocalyptic number.
It is an amenable number.
51404331201 is a deficient number, since it is larger than the sum of its proper divisors (17332297503).
51404331201 is a wasteful number, since it uses less digits than its factorization.
51404331201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49380111.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 51404331201 its reverse (10213340415), we get a palindrome (61617671616).
The spelling of 51404331201 in words is "fifty-one billion, four hundred four million, three hundred thirty-one thousand, two hundred one".
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