Base | Representation |
---|---|
bin | 101111110111111011… |
… | …111101100011000000 |
3 | 11220200110022120212112 |
4 | 233313323331203000 |
5 | 1320234002044300 |
6 | 35340445114452 |
7 | 3466563414545 |
oct | 576773754300 |
9 | 156613276775 |
10 | 51404331200 |
11 | 1a88944a952 |
12 | 9b67258a28 |
13 | 4b029a6a31 |
14 | 26b904cbcc |
15 | 150cce2e35 |
hex | bf7efd8c0 |
51404331200 has 42 divisors (see below), whose sum is σ = 126486786396. Its totient is φ = 20561731840.
The previous prime is 51404331197. The next prime is 51404331211. The reversal of 51404331200 is 213340415.
It is a super-2 number, since 2×514043312002 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 16062254 + ... + 16065453.
Almost surely, 251404331200 is an apocalyptic number.
51404331200 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
51404331200 is an abundant number, since it is smaller than the sum of its proper divisors (75082455196).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51404331200 is a wasteful number, since it uses less digits than its factorization.
51404331200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32127729 (or 32127714 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 51404331200 its reverse (213340415), we get a palindrome (51617671615).
The spelling of 51404331200 in words is "fifty-one billion, four hundred four million, three hundred thirty-one thousand, two hundred".
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