Base | Representation |
---|---|
bin | 100101011001110110011… |
… | …1110011001100001100111 |
3 | 200012110012011121122102111 |
4 | 1022303230332121201213 |
5 | 1133211232201311341 |
6 | 14533344144221451 |
7 | 1040256512454136 |
oct | 112635476314147 |
9 | 20173164548374 |
10 | 5140756666471 |
11 | 1702201134398 |
12 | 6b039100a887 |
13 | 2b3a046461aa |
14 | 13ab5769d91d |
15 | 8dac9aaa681 |
hex | 4acecf99867 |
5140756666471 has 2 divisors, whose sum is σ = 5140756666472. Its totient is φ = 5140756666470.
The previous prime is 5140756666459. The next prime is 5140756666537. The reversal of 5140756666471 is 1746666570415.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5140756666471 - 29 = 5140756665959 is a prime.
It is a super-3 number, since 3×51407566664713 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5140756646471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2570378333235 + 2570378333236.
It is an arithmetic number, because the mean of its divisors is an integer number (2570378333236).
Almost surely, 25140756666471 is an apocalyptic number.
5140756666471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5140756666471 is an equidigital number, since it uses as much as digits as its factorization.
5140756666471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25401600, while the sum is 58.
The spelling of 5140756666471 in words is "five trillion, one hundred forty billion, seven hundred fifty-six million, six hundred sixty-six thousand, four hundred seventy-one".
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