Base | Representation |
---|---|
bin | 111010011101011000010001… |
… | …0011100010101100101101111 |
3 | 2111102200010002121100101100202 |
4 | 1310322300202130111211233 |
5 | 1014344314111023300421 |
6 | 5021345214510344115 |
7 | 213211351642315124 |
oct | 16472604234254557 |
9 | 2442603077311322 |
10 | 514211242400111 |
11 | 13993084396a213 |
12 | 498097007bb03b |
13 | 190bcbb1b42859 |
14 | 90d9d57b3874b |
15 | 3e6ac33c4210b |
hex | 1d3ac2271596f |
514211242400111 has 32 divisors (see below), whose sum is σ = 548391611577600. Its totient is φ = 480480760258560.
The previous prime is 514211242400041. The next prime is 514211242400123. The reversal of 514211242400111 is 111004242112415.
It is a happy number.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-514211242400111 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (514211242490111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 19800951335 + ... + 19800977303.
It is an arithmetic number, because the mean of its divisors is an integer number (17137237861800).
Almost surely, 2514211242400111 is an apocalyptic number.
514211242400111 is a deficient number, since it is larger than the sum of its proper divisors (34180369177489).
514211242400111 is a wasteful number, since it uses less digits than its factorization.
514211242400111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41219.
The product of its (nonzero) digits is 2560, while the sum is 29.
Adding to 514211242400111 its reverse (111004242112415), we get a palindrome (625215484512526).
The spelling of 514211242400111 in words is "five hundred fourteen trillion, two hundred eleven billion, two hundred forty-two million, four hundred thousand, one hundred eleven".
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