Search a number
-
+
514212311999 is a prime number
BaseRepresentation
bin1110111101110010111…
…00010011001110111111
31211011021100011222010102
413132321130103032333
531411101322440444
61032120442231315
752102442351321
oct7367134231677
91734240158112
10514212311999
111890924988a1
12837a87b553b
133964a734c49
141ac609a5611
15d59870384e
hex77b97133bf

514212311999 has 2 divisors, whose sum is σ = 514212312000. Its totient is φ = 514212311998.

The previous prime is 514212311971. The next prime is 514212312001. The reversal of 514212311999 is 999113212415.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-514212311999 is a prime.

It is a super-2 number, since 2×5142123119992 (a number of 24 digits) contains 22 as substring.

Together with 514212312001, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (514212371999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257106155999 + 257106156000.

It is an arithmetic number, because the mean of its divisors is an integer number (257106156000).

Almost surely, 2514212311999 is an apocalyptic number.

514212311999 is a deficient number, since it is larger than the sum of its proper divisors (1).

514212311999 is an equidigital number, since it uses as much as digits as its factorization.

514212311999 is an evil number, because the sum of its binary digits is even.

The product of its digits is 174960, while the sum is 47.

The spelling of 514212311999 in words is "five hundred fourteen billion, two hundred twelve million, three hundred eleven thousand, nine hundred ninety-nine".