Base | Representation |
---|---|
bin | 1001100101001000… |
… | …11010011110010101 |
3 | 111021110011110022212 |
4 | 10302210122132111 |
5 | 41013200424332 |
6 | 2210212203205 |
7 | 241312645436 |
oct | 46244323625 |
9 | 14243143285 |
10 | 5143373717 |
11 | 21aa333889 |
12 | bb6609505 |
13 | 63c77a701 |
14 | 36b14348d |
15 | 2018278b2 |
hex | 13291a795 |
5143373717 has 4 divisors (see below), whose sum is σ = 5143607616. Its totient is φ = 5143139820.
The previous prime is 5143373671. The next prime is 5143373747. The reversal of 5143373717 is 7173733415.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 7173733415 = 5 ⋅1434746683.
It is a cyclic number.
It is not a de Polignac number, because 5143373717 - 210 = 5143372693 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5143373747) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80093 + ... + 129234.
It is an arithmetic number, because the mean of its divisors is an integer number (1285901904).
Almost surely, 25143373717 is an apocalyptic number.
It is an amenable number.
5143373717 is a deficient number, since it is larger than the sum of its proper divisors (233899).
5143373717 is a wasteful number, since it uses less digits than its factorization.
5143373717 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 233898.
The product of its digits is 185220, while the sum is 41.
The square root of 5143373717 is about 71717.3181107604. The cubic root of 5143373717 is about 1726.1665390412.
The spelling of 5143373717 in words is "five billion, one hundred forty-three million, three hundred seventy-three thousand, seven hundred seventeen".
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