Base | Representation |
---|---|
bin | 100101011011000101101… |
… | …0111100001100100000101 |
3 | 200012201001100221212121102 |
4 | 1022312023113201210011 |
5 | 1133232202444200000 |
6 | 14534503553225445 |
7 | 1040412411046115 |
oct | 112661327414405 |
9 | 20181040855542 |
10 | 5143414053125 |
11 | 1703345165307 |
12 | 6b09b2b62285 |
13 | 2b403905c72a |
14 | 13ad2a59d045 |
15 | 8dbd30243d5 |
hex | 4ad8b5e1905 |
5143414053125 has 48 divisors (see below), whose sum is σ = 6714526492800. Its totient is φ = 3935660760000.
The previous prime is 5143414053097. The next prime is 5143414053133. The reversal of 5143414053125 is 5213504143415.
5143414053125 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5143414053125 - 224 = 5143397275909 is a prime.
It is a super-3 number, since 3×51434140531253 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6444896 + ... + 7198854.
It is an arithmetic number, because the mean of its divisors is an integer number (139885968600).
Almost surely, 25143414053125 is an apocalyptic number.
It is an amenable number.
5143414053125 is a deficient number, since it is larger than the sum of its proper divisors (1571112439675).
5143414053125 is an frugal number, since it uses more digits than its factorization.
5143414053125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 754080 (or 754060 counting only the distinct ones).
The product of its (nonzero) digits is 144000, while the sum is 38.
The spelling of 5143414053125 in words is "five trillion, one hundred forty-three billion, four hundred fourteen million, fifty-three thousand, one hundred twenty-five".
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