Base | Representation |
---|---|
bin | 1110111110000010010… |
… | …11011110111101111101 |
3 | 1211011121101102222001211 |
4 | 13133001023132331331 |
5 | 31411333040340331 |
6 | 1032141400404421 |
7 | 52105606616236 |
oct | 7370113367575 |
9 | 1734541388054 |
10 | 514342121341 |
11 | 18914979a544 |
12 | 83824176711 |
13 | 3966b5b49c9 |
14 | 1ac73d1608d |
15 | d5a4ce58b1 |
hex | 77c12def7d |
514342121341 has 2 divisors, whose sum is σ = 514342121342. Its totient is φ = 514342121340.
The previous prime is 514342121333. The next prime is 514342121353. The reversal of 514342121341 is 143121243415.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 497795158116 + 16546963225 = 705546^2 + 128635^2 .
It is a cyclic number.
It is not a de Polignac number, because 514342121341 - 23 = 514342121333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (514342121311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257171060670 + 257171060671.
It is an arithmetic number, because the mean of its divisors is an integer number (257171060671).
Almost surely, 2514342121341 is an apocalyptic number.
It is an amenable number.
514342121341 is a deficient number, since it is larger than the sum of its proper divisors (1).
514342121341 is an equidigital number, since it uses as much as digits as its factorization.
514342121341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11520, while the sum is 31.
Adding to 514342121341 its reverse (143121243415), we get a palindrome (657463364756).
The spelling of 514342121341 in words is "five hundred fourteen billion, three hundred forty-two million, one hundred twenty-one thousand, three hundred forty-one".
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