Base | Representation |
---|---|
bin | 10111011000111101100110… |
… | …10110101111000000111111 |
3 | 20202010011100111001001210221 |
4 | 23230132303112233000333 |
5 | 23220203334031413012 |
6 | 301221005120042211 |
7 | 13556034154105552 |
oct | 1354366326570077 |
9 | 222104314031727 |
10 | 51435242451007 |
11 | 154306224a4448 |
12 | 59285b2763367 |
13 | 229142684c14c |
14 | c9b69c5d2699 |
15 | 5e2e36c92507 |
hex | 2ec7b35af03f |
51435242451007 has 2 divisors, whose sum is σ = 51435242451008. Its totient is φ = 51435242451006.
The previous prime is 51435242450983. The next prime is 51435242451031. The reversal of 51435242451007 is 70015424253415.
It is a balanced prime because it is at equal distance from previous prime (51435242450983) and next prime (51435242451031).
It is a cyclic number.
It is not a de Polignac number, because 51435242451007 - 211 = 51435242448959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51435242451097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25717621225503 + 25717621225504.
It is an arithmetic number, because the mean of its divisors is an integer number (25717621225504).
Almost surely, 251435242451007 is an apocalyptic number.
51435242451007 is a deficient number, since it is larger than the sum of its proper divisors (1).
51435242451007 is an equidigital number, since it uses as much as digits as its factorization.
51435242451007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672000, while the sum is 43.
The spelling of 51435242451007 in words is "fifty-one trillion, four hundred thirty-five billion, two hundred forty-two million, four hundred fifty-one thousand, seven".
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