Base | Representation |
---|---|
bin | 10111011001000111000101… |
… | …01000001001001011001111 |
3 | 20202010122111002010022001101 |
4 | 23230203202220021023033 |
5 | 23220244244102323210 |
6 | 301223210034523531 |
7 | 13556304225646063 |
oct | 1354434250111317 |
9 | 222118432108041 |
10 | 51440330511055 |
11 | 154327a3588252 |
12 | 59295927365a7 |
13 | 2291a57a00975 |
14 | c9ba22257aa3 |
15 | 5e31337e0a3a |
hex | 2ec8e2a092cf |
51440330511055 has 4 divisors (see below), whose sum is σ = 61728396613272. Its totient is φ = 41152264408840.
The previous prime is 51440330511007. The next prime is 51440330511113. The reversal of 51440330511055 is 55011503304415.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 51440330511055 - 223 = 51440322122447 is a prime.
It is a super-2 number, since 2×514403305110552 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5144033051101 + ... + 5144033051110.
It is an arithmetic number, because the mean of its divisors is an integer number (15432099153318).
Almost surely, 251440330511055 is an apocalyptic number.
51440330511055 is a deficient number, since it is larger than the sum of its proper divisors (10288066102217).
51440330511055 is a wasteful number, since it uses less digits than its factorization.
51440330511055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10288066102216.
The product of its (nonzero) digits is 90000, while the sum is 37.
The spelling of 51440330511055 in words is "fifty-one trillion, four hundred forty billion, three hundred thirty million, five hundred eleven thousand, fifty-five".
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