514404326141 has 2 divisors, whose sum is σ = 514404326142. Its totient is φ = 514404326140.

The previous prime is 514404326123. The next prime is 514404326143. The reversal of 514404326141 is 141623404415.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 281159760025 + 233244566116 = 530245^2 + 482954^2 .

It is a cyclic number.

It is not a de Polignac number, because 514404326141 - 2¹⁸ = 514404063997 is a prime.

It is a super-2 number, since 2×514404326141² (a number of 24 digits) contains 22 as substring.

Together with 514404326143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (514404326143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257202163070 + 257202163071.

It is an arithmetic number, because the mean of its divisors is an integer number (257202163071).

Almost surely, 2^514404326141 is an apocalyptic number.

It is an amenable number.

514404326141 is a deficient number, since it is larger than the sum of its proper divisors (1).

514404326141 is an equidigital number, since it uses as much as digits as its factorization.

514404326141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46080, while the sum is 35.

The spelling of 514404326141 in words is "five hundred fourteen billion, four hundred four million, three hundred twenty-six thousand, one hundred forty-one".