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514440421153 is a prime number
BaseRepresentation
bin1110111110001110000…
…10011101111100100001
31211011212020102010001121
413133013002131330201
531412033221434103
61032155231332241
752111212300511
oct7370702357441
91734766363047
10514440421153
1118919a22a65a
1283851081081
1339685a81689
141ac82dc3841
15d5ad7616bd
hex77c709df21

514440421153 has 2 divisors, whose sum is σ = 514440421154. Its totient is φ = 514440421152.

The previous prime is 514440421151. The next prime is 514440421163. The reversal of 514440421153 is 351124044415.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 390165135424 + 124275285729 = 624632^2 + 352527^2 .

It is a cyclic number.

It is not a de Polignac number, because 514440421153 - 21 = 514440421151 is a prime.

Together with 514440421151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (514440421151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257220210576 + 257220210577.

It is an arithmetic number, because the mean of its divisors is an integer number (257220210577).

Almost surely, 2514440421153 is an apocalyptic number.

It is an amenable number.

514440421153 is a deficient number, since it is larger than the sum of its proper divisors (1).

514440421153 is an equidigital number, since it uses as much as digits as its factorization.

514440421153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38400, while the sum is 34.

Adding to 514440421153 its reverse (351124044415), we get a palindrome (865564465568).

The spelling of 514440421153 in words is "five hundred fourteen billion, four hundred forty million, four hundred twenty-one thousand, one hundred fifty-three".