Base | Representation |
---|---|
bin | 111010011111001000110110… |
… | …0111110011110110000111111 |
3 | 2111110112020010212200110210001 |
4 | 1310332101230332132300333 |
5 | 1014412244231311030101 |
6 | 5022052241155255131 |
7 | 213235001124636361 |
oct | 16476215476366077 |
9 | 2443466125613701 |
10 | 514453011033151 |
11 | 139a14329a69653 |
12 | 498485345aa4a7 |
13 | 191099317710b8 |
14 | 9107931256d31 |
15 | 3e721840ac901 |
hex | 1d3e46cf9ec3f |
514453011033151 has 4 divisors (see below), whose sum is σ = 517859984616304. Its totient is φ = 511046037450000.
The previous prime is 514453011033139. The next prime is 514453011033167. The reversal of 514453011033151 is 151330110354415.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 514453011033151 - 237 = 514315572079679 is a prime.
It is a super-2 number, since 2×5144530110331512 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 514453011033151.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (514453018033151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1703486791350 + ... + 1703486791651.
It is an arithmetic number, because the mean of its divisors is an integer number (129464996154076).
Almost surely, 2514453011033151 is an apocalyptic number.
514453011033151 is a deficient number, since it is larger than the sum of its proper divisors (3406973583153).
514453011033151 is a wasteful number, since it uses less digits than its factorization.
514453011033151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3406973583152.
The product of its (nonzero) digits is 54000, while the sum is 37.
Adding to 514453011033151 its reverse (151330110354415), we get a palindrome (665783121387566).
The spelling of 514453011033151 in words is "five hundred fourteen trillion, four hundred fifty-three billion, eleven million, thirty-three thousand, one hundred fifty-one".
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