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51471468373 = 133959343721
BaseRepresentation
bin101111111011111100…
…000100011101010101
311220212010122111202111
4233323330010131111
51320403143441443
635351244111021
73501340156003
oct577374043525
9156763574674
1051471468373
111a913336016
129b85835471
134b13882480
1426c3d27a73
151513b5569d
hexbfbf04755

51471468373 has 4 divisors (see below), whose sum is σ = 55430812108. Its totient is φ = 47512124640.

The previous prime is 51471468353. The next prime is 51471468383. The reversal of 51471468373 is 37386417415.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 24050426724 + 27421041649 = 155082^2 + 165593^2 .

It is a cyclic number.

It is not a de Polignac number, because 51471468373 - 25 = 51471468341 is a prime.

It is a super-3 number, since 3×514714683733 (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51471468353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1979671848 + ... + 1979671873.

It is an arithmetic number, because the mean of its divisors is an integer number (13857703027).

Almost surely, 251471468373 is an apocalyptic number.

It is an amenable number.

51471468373 is a deficient number, since it is larger than the sum of its proper divisors (3959343735).

51471468373 is a wasteful number, since it uses less digits than its factorization.

51471468373 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3959343734.

The product of its digits is 1693440, while the sum is 49.

The spelling of 51471468373 in words is "fifty-one billion, four hundred seventy-one million, four hundred sixty-eight thousand, three hundred seventy-three".

Divisors: 1 13 3959343721 51471468373