Base | Representation |
---|---|
bin | 100101011110001101010… |
… | …0011100011010110001101 |
3 | 200020100100010001001020011 |
4 | 1022330122203203112031 |
5 | 1133334411444042331 |
6 | 14541532314553221 |
7 | 1041040362613666 |
oct | 112743243432615 |
9 | 20210303031204 |
10 | 5150111315341 |
11 | 1706171635563 |
12 | 6b2161a38811 |
13 | 2b4865719695 |
14 | 13b3a3c3236d |
15 | 8de75e8d3b1 |
hex | 4af1a8e358d |
5150111315341 has 2 divisors, whose sum is σ = 5150111315342. Its totient is φ = 5150111315340.
The previous prime is 5150111315333. The next prime is 5150111315357. The reversal of 5150111315341 is 1435131110515.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5093191376100 + 56919939241 = 2256810^2 + 238579^2 .
It is a cyclic number.
It is not a de Polignac number, because 5150111315341 - 23 = 5150111315333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5150111315311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2575055657670 + 2575055657671.
It is an arithmetic number, because the mean of its divisors is an integer number (2575055657671).
Almost surely, 25150111315341 is an apocalyptic number.
It is an amenable number.
5150111315341 is a deficient number, since it is larger than the sum of its proper divisors (1).
5150111315341 is an equidigital number, since it uses as much as digits as its factorization.
5150111315341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500, while the sum is 31.
Adding to 5150111315341 its reverse (1435131110515), we get a palindrome (6585242425856).
The spelling of 5150111315341 in words is "five trillion, one hundred fifty billion, one hundred eleven million, three hundred fifteen thousand, three hundred forty-one".
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