Base | Representation |
---|---|
bin | 110000000000001001… |
… | …101000110101110011 |
3 | 11221001001121200221210 |
4 | 300000021220311303 |
5 | 1321024241243011 |
6 | 35402250451203 |
7 | 3503155624425 |
oct | 600011506563 |
9 | 157031550853 |
10 | 51542134131 |
11 | 1a94a211274 |
12 | 9ba5433b03 |
13 | 4b253c5027 |
14 | 26cd480815 |
15 | 1519e636a6 |
hex | c00268d73 |
51542134131 has 8 divisors (see below), whose sum is σ = 72765365904. Its totient is φ = 32340162560.
The previous prime is 51542134117. The next prime is 51542134151. The reversal of 51542134131 is 13143124515.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51542134131 - 29 = 51542133619 is a prime.
It is a super-2 number, since 2×515421341312 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51542134151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 505314990 + ... + 505315091.
It is an arithmetic number, because the mean of its divisors is an integer number (9095670738).
Almost surely, 251542134131 is an apocalyptic number.
51542134131 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
51542134131 is a deficient number, since it is larger than the sum of its proper divisors (21223231773).
51542134131 is a wasteful number, since it uses less digits than its factorization.
51542134131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1010630101.
The product of its digits is 7200, while the sum is 30.
Adding to 51542134131 its reverse (13143124515), we get a palindrome (64685258646).
The spelling of 51542134131 in words is "fifty-one billion, five hundred forty-two million, one hundred thirty-four thousand, one hundred thirty-one".
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