Base | Representation |
---|---|
bin | 100101100000001010011… |
… | …1100101010100011000011 |
3 | 200020202011212202012222001 |
4 | 1023000110330222203003 |
5 | 1133422012410434220 |
6 | 14543505222324431 |
7 | 1041246442561144 |
oct | 113002474524303 |
9 | 20222155665861 |
10 | 5154312202435 |
11 | 1707a27958180 |
12 | 6b2b34889717 |
13 | 2b5084b460a6 |
14 | 13b681b19acb |
15 | 8e11eb9580a |
hex | 4b014f2a8c3 |
5154312202435 has 16 divisors (see below), whose sum is σ = 6747519350880. Its totient is φ = 3748559523840.
The previous prime is 5154312202421. The next prime is 5154312202451. The reversal of 5154312202435 is 5342022134515.
It is a happy number.
It is not a de Polignac number, because 5154312202435 - 27 = 5154312202307 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5154312202394 and 5154312202403.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7858189 + ... + 8488801.
It is an arithmetic number, because the mean of its divisors is an integer number (421719959430).
Almost surely, 25154312202435 is an apocalyptic number.
5154312202435 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5154312202435 is a deficient number, since it is larger than the sum of its proper divisors (1593207148445).
5154312202435 is a wasteful number, since it uses less digits than its factorization.
5154312202435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 779238.
The product of its (nonzero) digits is 144000, while the sum is 37.
The spelling of 5154312202435 in words is "five trillion, one hundred fifty-four billion, three hundred twelve million, two hundred two thousand, four hundred thirty-five".
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