Base | Representation |
---|---|
bin | 1111000000001100111… |
… | …00100010100000110101 |
3 | 1211021121101010201000210 |
4 | 13200012130202200311 |
5 | 31421223040021323 |
6 | 1032452552300033 |
7 | 52146450400503 |
oct | 7400634424065 |
9 | 1737541121023 |
10 | 515504220213 |
11 | 189695769634 |
12 | 83aa93a1619 |
13 | 397c5298a88 |
14 | 1ad443bb673 |
15 | d621d46293 |
hex | 7806722835 |
515504220213 has 16 divisors (see below), whose sum is σ = 710759987136. Its totient is φ = 332152529280.
The previous prime is 515504220211. The next prime is 515504220221. The reversal of 515504220213 is 312022405515.
It is not a de Polignac number, because 515504220213 - 21 = 515504220211 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (515504220211) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24184608 + ... + 24205913.
It is an arithmetic number, because the mean of its divisors is an integer number (44422499196).
Almost surely, 2515504220213 is an apocalyptic number.
515504220213 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
It is an amenable number.
515504220213 is a deficient number, since it is larger than the sum of its proper divisors (195255766923).
515504220213 is a wasteful number, since it uses less digits than its factorization.
515504220213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48390644.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 515504220213 its reverse (312022405515), we get a palindrome (827526625728).
The spelling of 515504220213 in words is "five hundred fifteen billion, five hundred four million, two hundred twenty thousand, two hundred thirteen".
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