Base | Representation |
---|---|
bin | 11110110000010… |
… | …001010000000101 |
3 | 1022221212222211222 |
4 | 132300101100011 |
5 | 2024042020203 |
6 | 123111010125 |
7 | 15533446604 |
oct | 3660212005 |
9 | 1287788758 |
10 | 515970053 |
11 | 245284a35 |
12 | 124969945 |
13 | 82b87131 |
14 | 4c751a3b |
15 | 30470038 |
hex | 1ec11405 |
515970053 has 2 divisors, whose sum is σ = 515970054. Its totient is φ = 515970052.
The previous prime is 515969977. The next prime is 515970067. The reversal of 515970053 is 350079515.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 350513284 + 165456769 = 18722^2 + 12863^2 .
It is a cyclic number.
It is not a de Polignac number, because 515970053 - 210 = 515969029 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 515969995 and 515970022.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (515970073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257985026 + 257985027.
It is an arithmetic number, because the mean of its divisors is an integer number (257985027).
Almost surely, 2515970053 is an apocalyptic number.
It is an amenable number.
515970053 is a deficient number, since it is larger than the sum of its proper divisors (1).
515970053 is an equidigital number, since it uses as much as digits as its factorization.
515970053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23625, while the sum is 35.
The square root of 515970053 is about 22714.9742020545. The cubic root of 515970053 is about 802.0624144269.
The spelling of 515970053 in words is "five hundred fifteen million, nine hundred seventy thousand, fifty-three".
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