Search a number
-
+
516961153349 is a prime number
BaseRepresentation
bin1111000010111010100…
…10010011000101000101
31211102100220121120120022
413201131102103011011
531432214023401344
61033253315344525
752230531205124
oct7413522230505
91742326546508
10516961153349
1118a273104003
12842352b2145
133999808c5a4
141b041aadabb
15d6a9bd50ee
hex785d493145

516961153349 has 2 divisors, whose sum is σ = 516961153350. Its totient is φ = 516961153348.

The previous prime is 516961153339. The next prime is 516961153351. The reversal of 516961153349 is 943351169615.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 505897900225 + 11063253124 = 711265^2 + 105182^2 .

It is a cyclic number.

It is not a de Polignac number, because 516961153349 - 24 = 516961153333 is a prime.

It is a super-3 number, since 3×5169611533493 (a number of 36 digits) contains 333 as substring.

Together with 516961153351, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 516961153349.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (516961153339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258480576674 + 258480576675.

It is an arithmetic number, because the mean of its divisors is an integer number (258480576675).

Almost surely, 2516961153349 is an apocalyptic number.

It is an amenable number.

516961153349 is a deficient number, since it is larger than the sum of its proper divisors (1).

516961153349 is an equidigital number, since it uses as much as digits as its factorization.

516961153349 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2624400, while the sum is 53.

The spelling of 516961153349 in words is "five hundred sixteen billion, nine hundred sixty-one million, one hundred fifty-three thousand, three hundred forty-nine".