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51742345901 is a prime number
BaseRepresentation
bin110000001100000101…
…011000101010101101
311221120000100111212112
4300030011120222231
51321432020032101
635434202013405
73511136453261
oct601405305255
9157500314775
1051742345901
111aa42229344
12a0404a7265
134b57a2482c
14270bcba0a1
15152c8106bb
hexc0c158aad

51742345901 has 2 divisors, whose sum is σ = 51742345902. Its totient is φ = 51742345900.

The previous prime is 51742345883. The next prime is 51742345903. The reversal of 51742345901 is 10954324715.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28942855876 + 22799490025 = 170126^2 + 150995^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51742345901 is a prime.

It is a Sophie Germain prime.

Together with 51742345903, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51742345903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25871172950 + 25871172951.

It is an arithmetic number, because the mean of its divisors is an integer number (25871172951).

Almost surely, 251742345901 is an apocalyptic number.

It is an amenable number.

51742345901 is a deficient number, since it is larger than the sum of its proper divisors (1).

51742345901 is an equidigital number, since it uses as much as digits as its factorization.

51742345901 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 41.

The spelling of 51742345901 in words is "fifty-one billion, seven hundred forty-two million, three hundred forty-five thousand, nine hundred one".