Base | Representation |
---|---|
bin | 100101101011100011110… |
… | …1000101010101011111111 |
3 | 200100002100102110222212212 |
4 | 1023113013220222223333 |
5 | 1134322122414341041 |
6 | 15003033445451035 |
7 | 1043104055330666 |
oct | 113270750525377 |
9 | 20302312428785 |
10 | 5178784918271 |
11 | 1717346091868 |
12 | 6b7824710a7b |
13 | 2b7485063733 |
14 | 13c924047ddd |
15 | 8eaa34108eb |
hex | 4b5c7a2aaff |
5178784918271 has 2 divisors, whose sum is σ = 5178784918272. Its totient is φ = 5178784918270.
The previous prime is 5178784918259. The next prime is 5178784918283. The reversal of 5178784918271 is 1728194878715.
It is a balanced prime because it is at equal distance from previous prime (5178784918259) and next prime (5178784918283).
It is a cyclic number.
It is not a de Polignac number, because 5178784918271 - 210 = 5178784917247 is a prime.
It is a super-2 number, since 2×51787849182712 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5178784918231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2589392459135 + 2589392459136.
It is an arithmetic number, because the mean of its divisors is an integer number (2589392459136).
Almost surely, 25178784918271 is an apocalyptic number.
5178784918271 is a deficient number, since it is larger than the sum of its proper divisors (1).
5178784918271 is an equidigital number, since it uses as much as digits as its factorization.
5178784918271 is an evil number, because the sum of its binary digits is even.
The product of its digits is 63221760, while the sum is 68.
The spelling of 5178784918271 in words is "five trillion, one hundred seventy-eight billion, seven hundred eighty-four million, nine hundred eighteen thousand, two hundred seventy-one".
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