Base | Representation |
---|---|
bin | 110000010001111011… |
… | …011110111001101101 |
3 | 11221210211212212001011 |
4 | 300101323132321231 |
5 | 1322132121211133 |
6 | 35452023545221 |
7 | 3513440146114 |
oct | 602173367155 |
9 | 157724785034 |
10 | 51840413293 |
11 | 1aa9261a879 |
12 | a0692bb211 |
13 | 4b7213c786 |
14 | 271ad26c7b |
15 | 15362326cd |
hex | c11edee6d |
51840413293 has 2 divisors, whose sum is σ = 51840413294. Its totient is φ = 51840413292.
The previous prime is 51840413281. The next prime is 51840413323. The reversal of 51840413293 is 39231404815.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30308372649 + 21532040644 = 174093^2 + 146738^2 .
It is a cyclic number.
It is not a de Polignac number, because 51840413293 - 213 = 51840405101 is a prime.
It is a super-2 number, since 2×518404132932 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51840413203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25920206646 + 25920206647.
It is an arithmetic number, because the mean of its divisors is an integer number (25920206647).
Almost surely, 251840413293 is an apocalyptic number.
It is an amenable number.
51840413293 is a deficient number, since it is larger than the sum of its proper divisors (1).
51840413293 is an equidigital number, since it uses as much as digits as its factorization.
51840413293 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 40.
The spelling of 51840413293 in words is "fifty-one billion, eight hundred forty million, four hundred thirteen thousand, two hundred ninety-three".
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