Base | Representation |
---|---|
bin | 110000010111100001… |
… | …111111110011011101 |
3 | 11222001101201122112211 |
4 | 300113201333303131 |
5 | 1322330201124423 |
6 | 35505222200421 |
7 | 3515661036052 |
oct | 602741776335 |
9 | 158041648484 |
10 | 51934395613 |
11 | 20030681111 |
12 | a094883111 |
13 | 4b88757209 |
14 | 27295cd029 |
15 | 153e5e910d |
hex | c1787fcdd |
51934395613 has 2 divisors, whose sum is σ = 51934395614. Its totient is φ = 51934395612.
The previous prime is 51934395559. The next prime is 51934395629. The reversal of 51934395613 is 31659343915.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 41214278169 + 10720117444 = 203013^2 + 103538^2 .
It is a cyclic number.
It is not a de Polignac number, because 51934395613 - 29 = 51934395101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51934395683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25967197806 + 25967197807.
It is an arithmetic number, because the mean of its divisors is an integer number (25967197807).
Almost surely, 251934395613 is an apocalyptic number.
It is an amenable number.
51934395613 is a deficient number, since it is larger than the sum of its proper divisors (1).
51934395613 is an equidigital number, since it uses as much as digits as its factorization.
51934395613 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1312200, while the sum is 49.
The spelling of 51934395613 in words is "fifty-one billion, nine hundred thirty-four million, three hundred ninety-five thousand, six hundred thirteen".
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