Base | Representation |
---|---|
bin | 110000011011000001… |
… | …111111011101000001 |
3 | 11222012111012212121221 |
4 | 300123001333131001 |
5 | 1322440214130213 |
6 | 35515120515041 |
7 | 3520303116001 |
oct | 603301773501 |
9 | 158174185557 |
10 | 51993114433 |
11 | 20060837467 |
12 | a0b047ba81 |
13 | 4b97975c90 |
14 | 2733316001 |
15 | 154484738d |
hex | c1b07f741 |
51993114433 has 64 divisors (see below), whose sum is σ = 61937568000. Its totient is φ = 43225104384.
The previous prime is 51993114401. The next prime is 51993114497. The reversal of 51993114433 is 33441139915.
51993114433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 51993114433 - 25 = 51993114401 is a prime.
It is a super-2 number, since 2×519931144332 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 51993114433.
It is not an unprimeable number, because it can be changed into a prime (51993114233) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 78896658 + ... + 78897316.
It is an arithmetic number, because the mean of its divisors is an integer number (967774500).
Almost surely, 251993114433 is an apocalyptic number.
It is an amenable number.
51993114433 is a deficient number, since it is larger than the sum of its proper divisors (9944453567).
51993114433 is a wasteful number, since it uses less digits than its factorization.
51993114433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 914.
The product of its digits is 174960, while the sum is 43.
The spelling of 51993114433 in words is "fifty-one billion, nine hundred ninety-three million, one hundred fourteen thousand, four hundred thirty-three".
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