Base | Representation |
---|---|
bin | 100101110110011000010… |
… | …0100110001111010100111 |
3 | 200102022022202000220010021 |
4 | 1023230300210301322213 |
5 | 1140212214201442323 |
6 | 15021435233340011 |
7 | 1044555625230256 |
oct | 113546044617247 |
9 | 20368282026107 |
10 | 5202020343463 |
11 | 172618995a6a9 |
12 | 70022a107607 |
13 | 2b9718b31338 |
14 | 13dac9cda79d |
15 | 904b322605d |
hex | 4bb30931ea7 |
5202020343463 has 2 divisors, whose sum is σ = 5202020343464. Its totient is φ = 5202020343462.
The previous prime is 5202020343461. The next prime is 5202020343473. The reversal of 5202020343463 is 3643430202025.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5202020343463 - 21 = 5202020343461 is a prime.
It is a super-3 number, since 3×52020203434633 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 5202020343461, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5202020343461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2601010171731 + 2601010171732.
It is an arithmetic number, because the mean of its divisors is an integer number (2601010171732).
Almost surely, 25202020343463 is an apocalyptic number.
5202020343463 is a deficient number, since it is larger than the sum of its proper divisors (1).
5202020343463 is an equidigital number, since it uses as much as digits as its factorization.
5202020343463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 34.
Adding to 5202020343463 its reverse (3643430202025), we get a palindrome (8845450545488).
The spelling of 5202020343463 in words is "five trillion, two hundred two billion, twenty million, three hundred forty-three thousand, four hundred sixty-three".
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