Base | Representation |
---|---|
bin | 100101110110110101111… |
… | …0100000010111110100101 |
3 | 200102101220000011002201001 |
4 | 1023231223310002332211 |
5 | 1140221233113420003 |
6 | 15022122015233301 |
7 | 1044622353666661 |
oct | 113555364027645 |
9 | 20371800132631 |
10 | 5203014201253 |
11 | 1726649968780 |
12 | 700466b18831 |
13 | 2b98469ca87b |
14 | 13db81cc98a1 |
15 | 905205e261d |
hex | 4bb6bd02fa5 |
5203014201253 has 4 divisors (see below), whose sum is σ = 5676015492288. Its totient is φ = 4730012910220.
The previous prime is 5203014201233. The next prime is 5203014201299. The reversal of 5203014201253 is 3521024103025.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5203014201253 - 213 = 5203014193061 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5203014201233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236500645501 + ... + 236500645522.
It is an arithmetic number, because the mean of its divisors is an integer number (1419003873072).
Almost surely, 25203014201253 is an apocalyptic number.
It is an amenable number.
5203014201253 is a deficient number, since it is larger than the sum of its proper divisors (473001291035).
5203014201253 is a wasteful number, since it uses less digits than its factorization.
5203014201253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 473001291034.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 5203014201253 its reverse (3521024103025), we get a palindrome (8724038304278).
The spelling of 5203014201253 in words is "five trillion, two hundred three billion, fourteen million, two hundred one thousand, two hundred fifty-three".
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