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5203420501341 = 312171425204191
BaseRepresentation
bin100101110111000010000…
…0001111101010101011101
3200102102221022200021122110
41023232010001331111131
51140223101122020331
615022230211504233
71044635416331226
oct113560401752535
920372838607573
105203420501341
111726838246a77
1270055abb8079
132b98acc3691a
1413dbbdc5024d
15905460ec946
hex4bb8407d55d

5203420501341 has 8 divisors (see below), whose sum is σ = 6943594823424. Its totient is φ = 3466096590080.

The previous prime is 5203420501267. The next prime is 5203420501373. The reversal of 5203420501341 is 1431050243025.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5203420501341 - 219 = 5203419977053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5203420501299 and 5203420501308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5203420501141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 712598445 + ... + 712605746.

It is an arithmetic number, because the mean of its divisors is an integer number (867949352928).

Almost surely, 25203420501341 is an apocalyptic number.

It is an amenable number.

5203420501341 is a deficient number, since it is larger than the sum of its proper divisors (1740174322083).

5203420501341 is a wasteful number, since it uses less digits than its factorization.

5203420501341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1425205411.

The product of its (nonzero) digits is 14400, while the sum is 30.

Adding to 5203420501341 its reverse (1431050243025), we get a palindrome (6634470744366).

The spelling of 5203420501341 in words is "five trillion, two hundred three billion, four hundred twenty million, five hundred one thousand, three hundred forty-one".

Divisors: 1 3 1217 3651 1425204191 4275612573 1734473500447 5203420501341