Base | Representation |
---|---|
bin | 100101110111011100100… |
… | …0011010101000100000101 |
3 | 200102112020022112012021211 |
4 | 1023232321003111010011 |
5 | 1140231411333200000 |
6 | 15022454350011421 |
7 | 1044666440362531 |
oct | 113567103250405 |
9 | 20375208465254 |
10 | 5204310053125 |
11 | 1727154392437 |
12 | 700768aa6b71 |
13 | 2b99c2312721 |
14 | 13dc6604abc1 |
15 | 905992637ba |
hex | 4bbb90d5105 |
5204310053125 has 24 divisors (see below), whose sum is σ = 6505689609216. Its totient is φ = 4162988250000.
The previous prime is 5204310053123. The next prime is 5204310053153. The reversal of 5204310053125 is 5213500134025.
It is not a de Polignac number, because 5204310053125 - 21 = 5204310053123 is a prime.
It is a super-3 number, since 3×52043100531253 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5204310053123) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 29759692 + ... + 29934058.
It is an arithmetic number, because the mean of its divisors is an integer number (271070400384).
Almost surely, 25204310053125 is an apocalyptic number.
It is an amenable number.
5204310053125 is a deficient number, since it is larger than the sum of its proper divisors (1301379556091).
5204310053125 is an frugal number, since it uses more digits than its factorization.
5204310053125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 183943 (or 183923 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 5204310053125 in words is "five trillion, two hundred four billion, three hundred ten million, fifty-three thousand, one hundred twenty-five".
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