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52044133 = 311678843
BaseRepresentation
bin1100011010001…
…0000101100101
310121221010010111
43012202011211
5101310403013
65055253021
71201240111
oct306420545
9117833114
1052044133
1127417589
121551a171
13aa2295b
146caa741
15488073d
hex31a2165

52044133 has 4 divisors (see below), whose sum is σ = 53723008. Its totient is φ = 50365260.

The previous prime is 52044131. The next prime is 52044137. The reversal of 52044133 is 33144025.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52044133 - 21 = 52044131 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52044131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 839391 + ... + 839452.

It is an arithmetic number, because the mean of its divisors is an integer number (13430752).

Almost surely, 252044133 is an apocalyptic number.

It is an amenable number.

52044133 is a deficient number, since it is larger than the sum of its proper divisors (1678875).

52044133 is a wasteful number, since it uses less digits than its factorization.

52044133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1678874.

The product of its (nonzero) digits is 1440, while the sum is 22.

The square root of 52044133 is about 7214.1619748935. The cubic root of 52044133 is about 373.3566799990.

Adding to 52044133 its reverse (33144025), we get a palindrome (85188158).

The spelling of 52044133 in words is "fifty-two million, forty-four thousand, one hundred thirty-three".

Divisors: 1 31 1678843 52044133